The void pointer, also known as the generic pointer, is a special type of pointer that can be pointed at objects of any data type! A void pointer is declared like a normal pointer, using the void keyword as the pointer’s type:
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void *ptr; // ptr is a void pointer |
A void pointer can point to objects of any data type:
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int nValue; float fValue; struct Something { int n; float f; }; Something sValue; void *ptr; ptr = &nValue; // valid ptr = &fValue; // valid ptr = &sValue; // valid |
However, because the void pointer does not know what type of object it is pointing to, it cannot be dereferenced directly! Rather, the void pointer must first be explicitly cast to another pointer type before it is dereferenced.
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int value = 5; void *ptr = &value; // cannot dereference ptr because it is a void pointer int *intPtr = static_cast<int*>(ptr); // cast from void* to int* cout << *intPtr << endl; // can dereference intPtr |
The next obvious questions is: If a void pointer doesn’t know what it’s pointing to, how do we know what to cast it to? Ultimately, that is up to you to keep track of.
Here’s an example of a void pointer in use:
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#include <iostream> enum Type { INT, FLOAT, CSTRING, }; void printValue(void *ptr, Type type) { switch (type) { case INT: std::cout << *static_cast<int*>(ptr) << '\n'; break; case FLOAT: std::cout << *static_cast<float*>(ptr) << '\n'; break; case CSTRING: std::cout << static_cast<char*>(ptr) << '\n'; break; } } int main() { int nValue = 5; float fValue = 7.5; char szValue[] = "Mollie"; printValue(&nValue, INT); printValue(&fValue, FLOAT); printValue(szValue, CSTRING); return 0; } |
This program prints:
5 7.5 Mollie
Void pointer miscellany
Void pointers can be set to a null value:
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void *ptr = 0; // ptr is a void pointer that is currently a null pointer |
Although some compilers allow deleting a void pointer that points to dynamically allocated memory, doing so should be avoided, as it can result in undefined behavior.
It is not possible to do pointer arithmetic on a void pointer. This is because pointer arithmetic requires the pointer to know what size object it is pointing to, so it can increment or decrement the pointer appropriately.
Note that there is no such thing as a void reference. This is because a void reference would be of type void &, and would not know what type of value it referenced.
Conclusion
In general, it is a good idea to avoid using void pointers unless absolutely necessary, as they effectively allow you to avoid type checking. This allows you to inadvertently do things that make no sense, and the compiler won’t complain about it. For example, the following would be valid:
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int nValue = 5; printValue(&nValue, CSTRING); |
But who knows what the result would actually be!
Although the above function seems like a neat way to make a single function handle multiple data types, C++ actually offers a much better way to do the same thing (via function overloading) that retains type checking to help prevent misuse. Many other places where void pointers would once be used to handle multiple data types are now better done using templates, which also offer strong type checking.
However, very occasionally, you may still find a reasonable use for the void pointer. Just make sure there isn’t a better (safer) way to do the same thing using other language mechanisms first!
Quiz
1) What’s the difference between a void pointer and a null pointer?
Quiz answers
 6.14 -- Pointers to pointers
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 Index
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 6.12 -- Member selection with pointers and references
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why when you use:
cout << static_cast(pValue) << endl; // without the (*) symbol, you get the whole word "molly", unlike the case you do the same but with an int type pointer, and get the direction that it is point to?
char *szValue = "Mollie"; // here you used pointer
or
char szValue[] = "Mollie";
cout<<szValue1<<endl; // it gives "mollie"
int numbers[5]={'1','2','3','4','5' };
cout<<numbers; // it gives 0x28fefc
It would be very helpful to have some practice (e.g. programs to write) with pointers and dynamic memory allocation here!
But thanks for a wonderful site Alex! Really fun.