Debug

In the member function version, the expression cents1 + 2 becomes function call cents1.operator+(2). Note that there is now only one explicit function parameter, and cents1 has become an object prefix. However, in lesson 13.10 -- The hidden “this” pointer, we mentioned that the compiler implicitly converts an object prefix into a hidden leftmost parameter named *this. So in actuality, cents1.operator+(2) becomes operator+(&cents1, 2), which is almost identical to the friend version.

In the member function version, the expression cents1 + 2 becomes function call cents1.operator+(2). Note that there is now only one explicit function parameter, and cents1 has become an object prefix. However, in lesson 13.10 -- The hidden “this” pointer, we mentioned that the compiler implicitly converts an object prefix into a hidden leftmost parameter named *this. So in actuality, cents1.operator+(2) becomes operator+(&cents1, 2), which is almost identical to the friend version.

Encoded ampersand: &
Normal ampersand: &

Encoded entity: &cents
Normal entity: &cents

Test1